Question

Hey frnds...
Solve this question ....​

Answer 1

Answer:

Let the number of rupees 5 coins be x.

then, the number of rupees 2 coins be 3x.

& number of rupees 1 coins be 160 - (x+3x)

= 160 - 4x

According to question,

5 × x + 2 × 3x + 1 (160 - 4x) = 300

Or, 5x + 6x + 160 - 4x =300

Or, 7x = 140

Or, x = 140/7

x = 20

Hence, the no. of rupees 5 coins = x = 20.

Therefore no.of rupees 2 coins = 3x = 3×20=60.

& no. of rupees 1 coins = 160-4x = 160-4×20

160 - 80 = 80.

Answer 2

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✺Answer:

♦️GiveN:

• Total amount he have Rs. 300
• Types of coins = Rs.1 ,Rs.2 and Rs.5
• Total Number of coins = 160
• The no. of Rs.2 coins is 3 times more than that of Rs.5 coins.

♦️To FinD:

• No. of coins of each denominations.

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✺Explanation of Q.

The person is having a total of Rs.300 in the form of coins of denominations Rs.1, Rs.2 and Rs.5. Total no. of coins = 160. The no. of Rs.2 coins is thrice of Rs.5 coins. So, we take a variable for the no. of coins of Rs. 5, then no. of Rs.2 would be three times the variable. And, then for Rs.1, it would 160 - (3 × variable + variable).

They will amount to Rs.300. So, we need to find the value that each denominations coins are contributing. Accordingly we can solve.

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✺Solution:

Let the no. of Rs.5 coins be x

Then the no. of Rs.2 coins will be 3x

We have, total no. of coins = 160, then

No. of Rs.1 coins = 160 - (3x + x) =160 - 4x

So, now we need to find out the value contributions of each denominations in a total of Rs.300

So, Total value of Rs.5 coins

= Rs.5 × x = Rs. 5x

Total value of Rs. 2 coins

= Rs.2 × 3x = Rs. 6x

Total value of Rs. 1 coins

= Rs.1 × (160 - 4x)= Rs. 160 - 4x

$\large{\ddag \:{ \boxed{ \bf{ \red{According \: to \: Question...}}}}}$

Now we have, all the values of each coins and the total amount, so now we can calculate,

$\large{ \rm{ \rightarrow \: 5x + 6x + (160 - 4x) = Rs.300}} \\ \\ \large{ \rm{ \rightarrow \: 5x + 6x - 4x +160 = Rs.300}} \\ \\ \large{ \rm{ \rightarrow \: 7x + 160 = Rs.300}} \\ \\ \large{ \rm{ \rightarrow \: 7x = Rs.140}} \\ \\ \large{ \rm{ \rightarrow \: x = \frac{Rs.140}{7} = Rs.20}}$

So, the number of Coin of denominations:

Rs. 5 = x = Rs. 20

Rs. 2 = 3x = Rs. 60

Rs. 1 = 160 - 4x = 160 - 4 × 20 = Rs.80

$\large{ \rm{ \therefore{ \underline{ \purple{the \: no. \: of \: coins \: of \: Rs.5 \: = 20}}}}} \\ \\ \large{ \rm{ \therefore{ \underline{ \purple{the \: no. \: of \: coins \: of \: Rs.2 = 60}}}}} \\ \\ \large{ \rm{ \therefore{ \underline{ \purple{the \: no. \: of \: coins \: of \: Rs.1 = 80}}}}}$

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