Question

HEY FRNDZZ!! CAN ANYONE HELP ME PLZZ!!
If cotA = 12/5, then the value of (sinA+cosA) × cosecA is: ???

Answer 1

Hey,

Given cotA = 12/5
= (sinA+CosA)*CosecA
= (sinA)*CosecA+(CosA)*(cosecA)
= (sinA)*(1/sinA)+cosA*(1/sinA)
= 1+cosA/sinA
= 1+cotA
= 1+12/5
= 5+12/5
= 17/5
Therefore result of the given problem is 17/5.

HOPE IT HELPS:-))

Answer 2

here is your answer

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