hey gays,
plz solve fast this question .
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here semi circles above length is 3
and opposite also has length 3
and total length 14
Now as radius of both + diameter of its adjacent one = 14-(3+3) = 14 -6 = 8
As 2r + 2r = 8
4r = 8
r= 2
.So Area of 4 semi circles = 4 pie r^2
= 4× 3.14 × 4 = 50.24
Now area of square formed between = ( diameter)^2 = (2r)^2 = 4 r^2 = 16
Now area of biggest square = 14^2 = 196
So area of shaded = 196 -( 50.24 +16)
= 196- ( 66.24)
= 129.76
and opposite also has length 3
and total length 14
Now as radius of both + diameter of its adjacent one = 14-(3+3) = 14 -6 = 8
As 2r + 2r = 8
4r = 8
r= 2
.So Area of 4 semi circles = 4 pie r^2
= 4× 3.14 × 4 = 50.24
Now area of square formed between = ( diameter)^2 = (2r)^2 = 4 r^2 = 16
Now area of biggest square = 14^2 = 196
So area of shaded = 196 -( 50.24 +16)
= 196- ( 66.24)
= 129.76
Answered by
1
∴ Area of shaded region = Area of a big square - Area of a small square - Area of a 4 semicircle.
∴ Area of shaded region=(196−16−25.12)cm square
=154.88cm square
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