Hey genius of chemistry solve above 2 questions
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(6)
Ionisation potential=16V
so, ionisation energy=16×e
Hence 16e= -13.6 (Z/1)^2
find out Z from here and use it to find energy difference from n=1 to n=2
(7)
R=0.529×(n^2)/Z
put the given values and u will have value of n... then max no. of electrons= 2n^2
Ionisation potential=16V
so, ionisation energy=16×e
Hence 16e= -13.6 (Z/1)^2
find out Z from here and use it to find energy difference from n=1 to n=2
(7)
R=0.529×(n^2)/Z
put the given values and u will have value of n... then max no. of electrons= 2n^2
ZiaAzhar89:
i think u made a mistake somewhere
ans of 6 is 12
and 7 is 32
7 me n ki value ka approximation karna parega... that gives u n=4
in 6 Z^2=-16e/13.6.... dont solve this value... just put it in energy difference equation and u will get answer 12eV
n one more thing.... thanks to press kar diya karo
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