Question

Hey Geniuses

please solve,

the partial pressure of Ethane over a solution containing 6.56 into 10^ (-3) gram of Ethane is 1 bar if the solution contains 5.00 into 10^-2 g of ethane , then what shall be the partial pressure of the gas?

[even you can copy from any website ,but solve anyhow]

Answer 1

$<I>$☞HEYA MATE☜

⚫ according to Henry’s law

.m = k x p

Substituting the given values in the above equation.

We get

6.56 x10-3 = k x 1

Or

k = 6.56 x10-3

Now when m = 5 x 10-2,

Then again substituting the given values in Henry’s law equation,we get

 5 x 10-2 = 6.56 x10-3 x p

Or

p = 7.62 bar

☃️HOPE IT HELPS UH ☃️

Answer 2

Hello mate!!

According to Henry’s law

.m = k x p

Substituting the given values in the above equation.

We get

6.56 x10-3 = k x 1

Or

k = 6.56 x10-3

Now when m = 5 x 10-2,

Then again substituting the given values in Henry’s law equation,we get

 5 x 10-2 = 6.56 x10-3 x p

Or

p = 7.62 bar


☃️HOPE IT HELPS UH ☃️