Hey Good Morning Guys❤️❤️
Consider four collinear points A, B, C and D in that order. Another point E is such that AB = BE = BC.
If DE2 = AD. CD, then find the measure (in degrees) of (∠CED + ∠BEA + ∠AEC – ∠CBE).
Copied Answer not allowed ⚠️
By Choudhary21 ❤️
Answers
Answered by
2
Given : Consider four collinear points A, B, C and D in that order. Another point E is such that AB = BE = BC.
DE² = AD.CD
To Find : ∠CED + ∠BEA + ∠AEC – ∠CBE
Solution:
AB = BE = BC
=> ΔABE & ΔCBE are isosceles right angle triangle
=> ∠BAE = ∠AEB = ∠CEB = ∠BCE = 45°
∠AEC = ∠CBE = 90°
DE² = BD² + BE²
DE² = AD.CD = (BD + AB). (BD - BC) = (BD + BE). (BD - BE)
= BD² - BE²
BD² + BE² = BD² - BE²
=> BE = 0 Hence AB = BC = 0
Looks mistake in Data
Learn More:
A,B and P are the three non-collinear points on a plane. The ...
https://brainly.in/question/13197890
let P be an interior point of a triangle ABC . let Q and R be the ...
https://brainly.in/question/9424932
Answered by
0
Answer:
here is answer dear friend
Attachments:
Similar questions