Question

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Carries 2 Marks

Class 11 CBSE

Answer 1

Let both the equal forces be F

The resultant will be

=

$\sqrt{(f { }^{2} + {f}^{2} + 2f.f.cos(theta)) }$

(theta is the angle between the forces).

=

$\sqrt{(2 {f }^{2} + o)} (cos(90) is \: o$

=

$\sqrt{2.f}$

=

$\sqrt{2.f } = 1414$

=

$f \: = 1.1414 \times \: 1000 \div \sqrt{2}$

=

$f \: = \: 1000n$

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