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The sum of the digit of a two digit number is 15 . The number obtained by interchanging the digit exceeds the given number by 9 . The number is
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One digit=x,another digit=15-x
Let x be the tens digit and 15-x is in ones digit.
actual no=10x+15-x=9x+15
When interchanged,=10(15-x)+x=150-10x+x=150-9x
ATQ
=>9x+15+9=150-9x
=>9x+9x=150-24
=>18x=126
=>x=126/18=7
The no.=9x7+15=63+15=78
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