hey guy z
balance this eq
Al2(OH)3 + H2CO3 ->AL2CO3 + H2O
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Answer:
This is an acid-base reaction (neutralization): Al(OH) 3 is a base, H2CO3 is an acid.
products (Al 2(CO 3) 3, H20)
1
Al(OH)3 + H2CO3 → H2O + A12(CO3)3
A1203 + H2CO3 H20 + A12(CO3)3
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