Question

hey guys....20 pts!
$2x + y = 19 \\ 2x - 3y = - 3$
solve this BY CRAMER'S RULE.​

Answer 1

Answer:

the answer for your question is given in the image

hope this answer will help you

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Answer 2

Answer:

$x=6.75 \\y = 5.5$

Step-by-step explanation:

Here, the only procedure you have to use is Linear Addition...

$a + b = c$

$a-b = c$

⇒ $(a+a) + (b-b) = (c+c)$

⇒ $2a = 2c$

⇒ $a = c...$

This method will only work when at least 2 terms are found up with it's conjugate.... I mean that the sum of those 2 numbers or the variable in the 'Linear Addition' must be 0.....

So, this is the procedure which we are going to subtract the 1st one with the 2nd one....

Let's try,

$2x + y = 19$

$-(2x - 3y = -3)$ ⇔ $-2x + 3y = 3$

Here, -2x is the conjugate of 2x, which means that their sum is = 0.... Hope you've got this...

So, when you add these linearly,

$(2x-2x) + (y + 3y) = (19+3)$

⇒ $4y = 22$

⇒ $y = \frac{22}{4} = 5.5$....

Now, you can replace the value with any of the equation in the question to find $x$....

$2x + y = 19$

⇒ $2x + 5.5 = 19$

⇒$2x = 19-5.5 = 13.5$

⇒$x = \frac{13.5}{2} = 6.75$....

Which finally gives you that,

$x=6.75 \\y = 5.5$

Hope my answer helps you...

I took some excess time to answer... I'm sorry for it..!