Question

Hey Guys ☺

#50points

Quadrilateral PQRS is an isosceles trapezium in which PS = QR = 41 units and height of the trapezium is 40 units . If PQ = 33 , then , what could be the ratio of the diagonal QS to its height

Answer 1

According to given sum,

In triangle QTR, AngleT = 90

By Pythagoras theorem,

QT^2 +TR^2= QR^2

=> QT =40units

=> QR=41units

substitute these values...

(40)^2 +TR^2= (41)^2

=> TR^2= (41)^2 -(40)^2

=> 1681-1600

=> 81

TR=> 9units .

similarly, SU => 9units.

In triangle QTS, AngleT = 90.

QT= 40units.

ST= SU+UT

=> 9+33

=> 42units.

By Pythagoras thereom,

QS^2 = QT^2 +TS^2

=> (40)^2+(42)^2

=> 1600+1764

=> 3364.

QS= root3364 = 58.

Ratio of diagnol QS to its height QT is

=> QS:QT

=> 58:40

=>29:20


:-)Hope it helps u.

Answer 2

Step-by-step explanation:

Please mark as brainlist answer.