Question

Hey Guys ☺

#50points

Two ships are sailing on the same side of a lighthouse . Observed from the top of the lighthouse their angles of depression are 30 & 45 . If the height of lighthouse is 250 m , then the distance between the two ships is _________

Answer 1

here is your answer
250√3-250
= 183.01 (approximately)

Answer 2

Hey. sister !!!


here is your answer !!!


two ships are sailings on same side !



they both are in same direction !!!



now ,

height of lighthouse is => 250 m


and ,

the angle of depression is => 30 ° and 45 °


now , for easy convence. :- look the attachment :-




here =>

tan 30 ° = perpendicular / base



{ tan 30 ° = 1/ √ 2 }





1 / √ 3 = AD / BD

or. AD = 250 m


hence ,

BD = √ 3 × 250 ----------------(1)




now ,


tan 45 ° =. AD / CD



1 = AD / CD


{ AD = 250 m , tan45 ° = 1 }



CD = 250m



now ,

distance , between ships = BD - CD


=> √ 3 × 250. - 250


=> 250 ( √ 3 -1 )



=> 250 × 0.73


=> 182 .5 ( approx )



hence , the distance between ships is 183



hope it helps you sister !!!


thanks !!!





$thanks$