Math, asked by helpingpoint03, 1 month ago

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A and B can do a bit of work in 12 days. B and C can do it in 15 days while C and A can do it in 20 days. In how long will they complete it cooperating? Additionally, in how long can A alone do it?​

Answers

Answered by BrainlyYuVa
7

Solution

Given :-

  • Working day of (A + B) = 12
  • Working days of (B + C) = 15
  • Working days of ( C + A) = 20

Find :-

  • working days of A

Explanation

According to question,

  • (A + B )'s 1 days work = 1/12
  • (B + C)'s 1 days work = 1/15
  • (C + A)'s 1 days work = 1/20

then ,

Including 1 days work be

==> 2(A + B + C) = ( 1/12 + 1/15 + 1/20)

==> 2(A + B + C) = ( 5 + 4 +3)/60

==> 2(A + B + C) = 12/60

==> 2(A + B + C) = 1/5

==> ( A + B + C) = 1/10 .

Since

  • If they working together then, they can complete work in 10 days.

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Now, Calculate working days of A if he work alone

==> A's 1 days work = 1/10 - 1/15

==> A's 1 days work = ( 6 - 4)/60

==> A's 1 days work = 2/60

==> A's 1 days work = 1/30

Hence

  • A can complete work in 30 days if they work alone .

________________________

Answered by pc7292348
0

Answer:

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