Question

hey guys,

A stone piece weight 144 gf in air and 88 gf in water. how much will it weigh in kerosene oil of relative density 0.8?

Answer 1

here,

weight of the stone piece in air, W1 = 144 gf

weight of the stone piece is water, W2 = 88gf

and relative density of kerosene oil be W3.

relative density of the liquid =
$\frac{loss \: in \: weight \: of \: the \: stone \: in \: kerosene \: oil}{ loss \: in \: weight \: of \: the \: stone \: in \: water}$

$0.8 = \frac{144 - w3 }{144 - 88 } \\ = w3 = 91.2gf$

I hope this helps you!
@vaibhav246