Math, asked by Anonymous, 9 months ago

hey guys...another question...


need explanation with correct steps....​

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Answered by RvChaudharY50
16

Given :-

  • Anuj can Complete Whole work Alone in = 20 days.
  • Vikram can Complete Whole work Alone in = 30 days.
  • Sameer can Complete Whole work Alone in = 60 days.
  • Anuj Start working Alone and on Every Third day Takes Help of vikram and Sameer .

Solution :-

LCM of 20, 30 & 60 = 60 unit = Let Total work.

So,

Efficiency of Anuj = (Total Work) / (Total Days) = (60/20) = 3 unit / day.

Efficiency of Vikram = (Total Work) / (Total Days) = (60/30) = 2 unit / day.

→ Efficiency of Sameer = (Total Work) / (Total Days) = (60/60) = 1 unit / day.

_____________________

Now, From Given Data, we Can Say That,

in First 2 days Anuj Work alone , So, He complete = 2*3 = 6 unit of work in 2 days.

Now, in Third day, Vikram and Sameer also Join with Him,

So, Now, Total work Done in 3rd day = 3 + 2 + 1 = 6 unit.

So, we can say That:-

in 3 day work completed = 6 + 6 = 12 unit.

Now, we Have To Complete 60 units of work.

So,

12 units of work done in = 3 days.

→ 60 units of work done in = (3/12) * 60 = 15 days.

Hence, The whole work will Complete in 15 days.

Answered by Anonymous
0

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