Question

hey guys answer now❤️❤️❤️❤️
A student secures 90% 60% and 54% marks in test papers with 100, 150 and 200
respectively as maximum marks. Find the percentage of his aggregate.​

Answer 1

ANSWER:-

Given:

A student secures 90%, 60% & 54% marks in test paper with 100, 150 & 200 respectively.

To find:

The percentage of his aggregate.

Solution:

1st term:

90% of 100

$= > \frac{90}{100} \times 100 \\ \\ = > 90$

2nd term:

60% of 150

$= > \frac{60}{100} \times 150 \\ \\ = > 90$

3rd term:

54% of 200

$= > \frac{54}{100} \times 200 \\ \\ = > 108$

So,

Total marks secured by the student;

=) 90 + 90 + 108

=) 180 + 108

=) 288

&

Total maximum marks= 100+150+ 200

=) 450

Therefore,

Aggregate Percentage:

$= > \frac{288}{450} \times 100 \\ \\ = > 64\%$

Thus,

The aggregate of his percentage is 64%.

Hope it helps ☺️

Answer 2

SOLUTION:-

We have,

A student gains 90%, 60% & 54% marks in test paper with 100, 150 & 200.

To find:

The percentage of his aggregate.

According to the question:

1️⃣ 90% of 100

$= > \frac{90}{100} \times 100 \\ \\ = > 90$

2️⃣60% of 150

$= > \frac{60}{100} \times 150 \\ \\ = > 15 \times 6 \\ \\ = > 90$

3️⃣54% of 200

$= > \frac{54}{100} \times 200 \\ \\ = > 54 \times 2 \\ \\ = > 108$

So,

•Total marks gain by the student:

=) 90 + 90 + 108

=) 180 + 108

=) 288

&

•Total maximum marks:

=) 100 + 150 + 200

=) 450

Now,

•Aggregate Percentage(%):

$= > \frac{288}{450} \times 100 \\ \\ = > \frac{288}{45} \times 10 \\ \\ = > \frac{2880}{45} \\ \\ = > 64\%$

Thus,

The aggregate percentage is 64%.

Hope it helps ☺️