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We know that mean of acceleration on peripheral points on Pulley is equal to the acceleration on central point .
Because string on B side is attached so acceleration at point B is 0 but that on point connected to A has acceleration let 'a' . So the acceleration on central point becomes (a+0)/2
=> a/2
Now since acceleration on block a is double of that on central
Hence , displacement of block is also double of central point i.e. Pulley
=> displacement of block be x then that of Pulley becomes 2x
Hence , proved and we have also calculated the acceleration on block and Pulley !!
Hope it helps you !!!
Thank you
We know that mean of acceleration on peripheral points on Pulley is equal to the acceleration on central point .
Because string on B side is attached so acceleration at point B is 0 but that on point connected to A has acceleration let 'a' . So the acceleration on central point becomes (a+0)/2
=> a/2
Now since acceleration on block a is double of that on central
Hence , displacement of block is also double of central point i.e. Pulley
=> displacement of block be x then that of Pulley becomes 2x
Hence , proved and we have also calculated the acceleration on block and Pulley !!
Hope it helps you !!!
Thank you
shaym1210:
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