Question

hey guys:-

Answer the question:-❗

detailed required​

Answer 1

Answer:-

If you compare the energy in both situations you'll have this:

Consider the potential energy = mgh and the kinetic energy = V²/2

First:

mgh₁ = V²/2

Second:

mgh₂ = (4•V)²/2

So,

mgh₂ = 8•V²

Comparing both equations:

mgh₂/8 = mgh₁•2 → h₂/h₁ = 16 (d)

Hope it helps u mark as brainliest please

Answer 2

⭐《QUESTION》
An archer practicing an arrow bow shoots an arrow straight two times.The first time it's initial speed is V° and second time he increases the speed to 4V°. How would you compare the Maximum Height in the second trial to that of the first trial ?

⭐《ANSWER》

↪Actually welcome to the concept of the STRAIGHT PROJECTILE MOTION

↪ Since here the arrow acts as a projectile , here the angle of inclination is 90° , since it is straight upward direction

↪Then we apply here the formula for the Maximum height that is

↪Hmax = u^2 sin^2 ⊙ ÷ 2g

↪Solving simultaneously we get

↪H1 = V°^2/20 and H2 = 16V°^2/20

↪comparing the ratio we get

↪H1:H2 = 1:16

↪thus the answer is ⭐D.) 16 times greater