Question

hey guys answer the question please plz
the acute angle between the lines represented by 3x²-4√3xy+3y²=0

Answer 1

Comparing with equation $ax^2+ 2hxy+by^2=0$, we find that
$a=3$
$h=-2\sqrt{3}$
$b=3$
Using formula

$\mathrm{tan}\theta=2\frac{ \sqrt{h^2-ab}}{a+b}, \\ \mathrm{tan} \theta= \frac{ \sqrt{3}\times 2}{6}\\ \mathrm{And \: hence} \: tan\theta =\frac{1}{\sqrt{3}}$

Answer 2

Answer:

Step-by-step explanation:

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