Question

hey guys answer these questions plzz with explanation...
I will mark brainliest...
plzz it's really urgent...

Answer 1

10.66×10^(-27) is correct answer for 29 question

Answer 2

(1)20ev = 3.204 × 10^-18 joules  π(wavelength) = h c / E = 62.1nm  From Debroglie's realtion  π = h/p  Therefore, p = h/π  =(a) 1.066×10^-2 (2)The ionization energy is the energy to remove the electron from the bound state. Now here the electron is in an excited state. So depending on the excited state the electron is in, the ionization energy will be 3.4 eV or less. (3)lambda2=600×300/600-300 =600