Math, asked by muski20, 9 months ago

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A can finish a work in 12 days and B can do it in 15 days after A had worked for 3 days B also joined A to finish the remaining work in how many days the remaining work will be finished? ​

Answers

Answered by studymaterial72
3

Answer:

5 days

Step-by-step explanation:

LCM of 12 and 15 =60

Hence consider the quantum of work to be 60 units.

A can finish the job of 60 units in 12 days.. ..Hence, per day A does 5 units of work.

Similarly, B does 4 units of work per day.

For 3 days, A does the job alone…..which means he completes 5*3=15 units of work.

Hence balance work remaining = 60–15 = 45 units

A and B combined can finish (5+4)=9 units of work per day.

They will take 45 units / 9 units/day =5 days to complete the remaining work.

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Answered by eflanita1986
6

Answer:

5 days is the correct answer

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