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C)HOCl
D) HClO2
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Answers
QUESTION :
Of the four oxyacids of chlorine , the strongest oxidizing agent in dilute aqueous solution is :
A) HClO₄
B) HClO₃
C)HClO
D) HClO₂
ANSWER :
OPTION C
EXPLANATION :
Oxidation depends on oxidation number of the compound .
In the OPTION C , the oxidation number is the least .
The oxidation number of all other compounds are more .
Note that oxygen is more electropositive than chlorine .
Also remember that the power of oxidizing property of an element is inversely proportional to the oxidation number of that element .
The less the oxidation number the more will be the oxidizing property .
The more the oxidation number the less will be the oxidation property .
Hence the least oxidation number will be the strongest oxidizing agent.
Since the number of oxygen atoms in HClO is least , it has the least oxidation number as oxygen is more electropositive than chlorine .
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