Question

hey guys can anybody answer it

x+y+z=1 xy+yz+zx=-1 xyz=-1

Answer 1

are you sure this question is right

Answer 2

Given

x+y+z=1,xy+yz+zx=−1 and xyz=−1

x3+y3+z3−3xyz=(x+y+z)(x2+y2+z2−xy−yz−zx)

x3+y3+z3−3(−1)=1(x2+y2+z2)−(−1)

x3+y3+z3+3=x2+y2+z2+1

x3+y3+z3+2=x2+y2+z2

(x+y+z)2=x2+y2+z2+2xy+2yz+2xz

12=x2+y2+z2+2(−1)

x2+y2+z2=1+2

x2+y2+z2=3

x3+y3+z3+2=3

x3+y3+z3=1