Question

hey guys can u plzz answer this​

Answer 1

Answer:

x^2 - 9

Step-by-step explanation:

Given that,

Zeroes of a quadratic Polynomial are,

• log_2 (8)
• log_10 (0.001)

To find the quadratic Polynomial.

First of all, we have to simplify the zeroes.

Therefore, we will get,

$log_{2}(8) \\ \\ = log_{2}( {2}^{3} ) \\ \\ = 3 log_{2}(2) \\ \\ = 3 \times 1 \\ \\ = 3$

And,

$log_{10}(0.001) \\ \\ = log_{10}( \frac{1}{1000} ) \\ \\ = log_{10}( \frac{1}{ {10}^{3} } ) \\ \\ = log_{10}( {10}^{ - 3} ) \\ \\ = - 3 log_{10}(10) \\ \\ = - 3 \times 1 \\ \\ = - 3$

Therefore, we have,

The zereos are 3 and -3.

=> Sum of zeroes = 0

=> Product of zeroes = -9

Now, we know that,

A quadratic polynomial is given by,

x^2 -(sum of zeroes)x + (product of zereos)

Therefore, we will get,

= x^2 - 0(x) + (-9)

= x^2 - 9

Hence, required polynomial is x^2 - 9.

Answer 2

Hi friend I am sorry to say that...its a spam from verified answer..

Sorry..(._.)

Answer:

x^2 - 9

Step-by-step explanation:

Given that,

Zeroes of a quadratic Polynomial are,

log_2 (8)

log_10 (0.001)

To find the quadratic Polynomial.

First of all, we have to simplify the zeroes.

Therefore, we will get,

And,

Therefore, we have,

The zereos are 3 and -3.

=> Sum of zeroes = 0

=> Product of zeroes = -9

Now, we know that,

A quadratic polynomial is given by,

x^2 -(sum of zeroes)x + (product of zereos)

Therefore, we will get,

= x^2 - 0(x) + (-9)

= x^2 - 9

Hence, required polynomial is x^2 - 9.