Question

Hey guys❣..

Derive an expression for moment of inertia of a thin circular and perpendicular to the plane of the Ring.​

Answer 1

Answer:

The non-uniform ring has a mass M and radius R . Moment of inertia of a small piece with mass ms about an axis passing through the center of the ring and perpendicular to its plane will be msR2 m s R 2 .

Answer 2

$\textbf{Answer is in attachment!}$