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Answer 1

Answer:

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Here is your answer

Ans 1: If you observe the velocity time graph from time t=0 to t=10s, you will find that the velocity has increased and in away, its straight. Thus, we can conclude Uniform acceleration motion

Ans 2: If you observe the velocity time graph from time t=10s to t=30s, you will find that velocity is constant that is 40 m/s. Thus it is Uniform non accelerated motion

Ans 3: On observing from t=30s to t=50s, the velocity decreases in a straight line. That means Uniform decelerated motion.

Ans 4: We know acceleration is the slope of the velocity-time graph,

In mathematics, slope = tan Θ

Thus, tan Θ = $\frac{perpendicular}{base}$

slope  = $\frac{40}{10}$ m/s²

Acceleration is 4 m/s²

Ans 5: As acceleration is tan Θ,

here Θ is 0° as the line is ║

Thus acceleration is tan 0°

                            = 0 m/s²

Ans 6: Slope of B to C is $\frac{40}{50 - 30}$

    acceleration is $\frac{40}{20}$

    Acceleration = 2 m/s²

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Answer 2

Answer:

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