Question

HEY GUYS enjoy (20 marks)...

Two different dice are tossed together . find the probability :
1. of getting a doublet .
2. of getting a sum 10 , of the numbers on the two dice .

Answer 1

The respected answer is (1) 2 upon 12 is equal to 1 upon 6.may help you

Answer 2

Hey!
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★Probability ★
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=> The following outcomes are recorded when two dice are rolled together :

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( 1 , 1 ) ( 1 , 2 ) ( 1 , 3 ) ( 1 , 4 ) ( 1 , 5 ) ( 1 , 6 )

( 2 ,1 ) ( 2 , 2 ) ( 2 , 3 ) ( 2 , 4 ) ( 2 ,5 ) ( 2 ,6 )

( 3, 1 ) ( 3 ,2 ) ( 3, 3 ) ( 3,4 ) ( 3 , 5 ) ( 3 , 6 )

( 4 , 1 ) ( 4 ,2 ) ( 4, 3 ) ( 4, 4) ( 4,5 ) ( 4, 6)

( 5, 1 ) ( 5,2 ) (5, 3 ) (5, 4 ) ( 5 , 5 ) ( 5 , 6 )

(6, 1 ) ( 6, 2 ) ( 6, 3 ) ( 6, 4 ) ( 6, 5 ) ( 6 , 6 )
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→ Probability = Favourable Conditions / Total Outcomes

→ Here , Total Outcomes = 6 × 6 = 36




1. Probability of Doublet

➡Favourable Outcome [ (1, 1 ) (2,2) ( 3 ,3) (4 ,4) (5 ,5) (6 ,6 ) => 6



•°• P ( Doublet) = 6 / 36


=> 1 / 6 ✔
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2. Probability of sum 10


➡ Favourable conditions = ( 4 , 6 ) (5 , 5 ) ( 6 ,4 ) => 3


•°• P ( Sum 10 ) = 3 / 36


=> 1 / 12 ✔


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