Question

☆hey guys explain step by step☆ no spamming...
1) how many moles of glucose are present in 16% glucose solution​

Answer 1

Glucose -> C₆H₁₂O₆ .

Molecular mass = 16×6 + 1×12 + 12×6 = 96 + 12 + 72

= 180g

16% of 180g.

=>16/100×180

=> 28.8g

In 1g = 6.022 × $10^24$

In 28.8g = 6.022/28.8 × $10^24$ = 2.09 ans.

I hope its ryt..

Thanks and Regards.