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simplify and find the value of the following expressions, when a = 3 and b =1
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Answered by
2
4(a^2+b^2+2ab)-[4(a^2+b^2-2ab)-{-b^3+4(a-3)}]
4(a+b)^2-[4(a-b)^2-{b^3+4(a-3)}]
substitute a=3,b=1
4(3+1)^2-[4(3-1)^2-{1^3+4(3-3)}]
64-[16{1+0}]
64-16
48
4(a+b)^2-[4(a-b)^2-{b^3+4(a-3)}]
substitute a=3,b=1
4(3+1)^2-[4(3-1)^2-{1^3+4(3-3)}]
64-[16{1+0}]
64-16
48
Answered by
1
Answer:
47
Step-by-step explanation:
4(3*3+1*1+2*1*3)-[4(3*3+1*1-2*3*1)-{-1*-1*-1+4(3-3)}]
4(9+1+6)-[4(9+1-6)-{-1+0}]
4(16)-[4(4)+1]
64-[16+1]
64-17
47
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