Math, asked by shruti202068, 11 months ago

Hey guys, Give me all formulas of Trigonometry​

Answers

Answered by AdorableMe
185

sin θ = Opposite Side/Hypotenuse

sec θ = Hypotenuse/Adjacent Side

cos θ = Adjacent Side/Hypotenuse

tan θ = Opposite Side/Adjacent Side

cosec θ = Hypotenuse/Opposite Side

cot θ = Adjacent Side/Opposite Side

cosec θ = 1/sin θ

sec θ = 1/cos θ

cot θ = 1/tan θ

sin θ = 1/cosec θ

cos θ = 1/sec θ

tan θ = 1/cot θ

sin(x+2πn) = sin x

cos(x+2πn) = cos x

tan(x+πn) = tan x

cot(x+πn) = cot x

sec(x+2πn) = sec x

csc(x+2πn) = csc x

sin(x+2πn) = sin x

cos(x+2πn) = cos x

tan(x+πn) = tan x

cot(x+πn) = cot x

sec(x+2πn) = sec x

csc(x+2πn) = csc x

sin(x+y) = sin(x)cos(y)+cos(x)sin(y)

cos(x+y) = cos(x)cos(y)–sin(x)sin(y)

tan(x+y) = (tan x + tan y)/ (1−tan x •tan y)

sin(x–y) = sin(x)cos(y)–cos(x)sin(y)

cos(x–y) = cos(x)cos(y) + sin(x)sin(y)

tan(x−y) = (tan x–tan y)/ (1+tan x • tan y)

sin(2x) = 2sin(x) • cos(x) = [2tan x/(1+tan2 x)]

cos(2x) = cos2(x)–sin2(x) = [(1-tan2 x)/(1+tan2 x)]

cos(2x) = 2cos2(x)−1 = 1–2sin2(x)

tan(2x) = [2tan(x)]/ [1−tan2(x)]

sec (2x) = sec2 x/(2-sec2 x)

cosec (2x) = (sec x. csc x)/2

Answered by Anonymous
0

Answer:

All the formula is in the attachment

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