Question

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Q.A car of mass 1000kg is moving uniformly at 10ms^1.If the engine of car of the develope an extra linear momentum of 1000kg ms^-1.Calculate the new velocity with the car runs.✔

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Answer 1

In this case, we’ll see the net force acting on the vehicle.

Net force = 1000N — 500N = 500N.

Now, just recall a formula,

V = u + at. Here, V is the final velocity, u is the initial velocity, a is the acceleration and t is time taken.

So, we've

Time = 10 second

Initial velocity = 10 m/s.

Acceleration = Force / mass = 500/1000 = 0.5 m/s^2.

Therefore,

V = 10 + 0.5*10 => 10 + 5 =15m/s.

Therefore, the speed after 10 seconds will be 15 m/s or 54 km/h.

Answer 2

Hi !

Solution :-

given = mass of car = 1000Kg , v1 = 10m/s, Developed momentum = 1000kgm/s ,

New velocity , v2 = ?

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So , momentum m = M×v1

m = 1000 * 10 = 10000kgm/s

Total momentum = 10000 + 1000 = 11000kgm/s

*Using conservation of momentum theorem .*

m1v1 = m2v2

11000kgm/s = 1000 kg * v2

v2 = 11000 /1000 = 11m/s

since, new velocity = 11m/s Answer ✔

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Hope it helps you !!

@Raj❤