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Given nth term, an = (-1)n-1 5n+1
On substituting n = 1, 2, 3, 4, 5, we get
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Given, nth term of a sequence an = n (n + 2) On substituting n = 1, 2, 3, 4, and 5, we get the first five terms a1 = 1(1 + 2) = 3 a2 = 2(2 + 2) = 8 a3 = 3(3 + 2) = 15 a4 = 4(4 + 2) = 24 a5 = 5(5 + 2) = 35 Hence, the required terms are 3, 8, 15, 24, and 35. Hence, the required terms are 1/2, 2/3, 3/4, 4/5 and 5/6.
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