Question

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If cos theta + sin theta = 2 cos √2, show that cos theta - sin theta = √2 sin theta....

Answer 1

Answer:

Step-by-step explanation:

cosA+sinA= \sqrt{2}cosA \\ =>cos^2A+sin^2A+2cosAsinA=2cos^2A \\ =>-cos^2A+2cosAsinA-sin^2a=-2sin^2A \\ =>-(cosA-sinA)^2=-2sin^2A \\ =>cosA-sinA=\sqrt{2}sinA

Answer 2

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