Question

Hey guys help me in solving this question!​

Answer 1

$\:\: \underline{\underline{\bf{\large\mathfrak{~~Solution~~}}}}$

$\frac{1}{x} - \frac{1}{x - 2} = 3 \\ = > \frac{x - 2 - x}{x(x - 2)} = 3 \\ = > 3 x {}^{2} - 6x + 2 = 0 \\ \\ x = \frac{6 + \sqrt{4 - 4(3)(2)} }{6} \\ \\ here \: we \: can \: see \: that \\ \sqrt{4 - 24} = \sqrt{ - 20} is \: an \: imaginry \: number \: \\ so \: this \: equation \: will \: not \: give \: \\ any \: real \: solution \: or \: zeroes$

$:\: \underline{\underline{\bf{\large\mathfrak{~hope ~this ~help~you~~}}}}$