hey guys help me with this..
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Answered by
1
Answer:
∆BAC is congruent to ∆DAC
Step-by-step explanation:
In ∆BAC and ∆DAC,
Angle BAC = Angle DAC (Given)
BA = AD (Given)
AC = AC (Common)
Hence ∆BAC is congruent to ∆DAC
pls mark me as brainliest
Answered by
0
Answer: AC is common for both the triangles
Step-by-step explanation: this is the solution for problem 2
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