Question

hey guys ,
help me with this question

Answer 1

using heron formula

we get

area 336

area of parallelogram 336

bh/2=336

28h/2=336

14h=336

h=24

Answer 2

Answer:

• Sides of the triangle given
• 26cm,30cm,28cm

$also \: given \:the \: triangle \: and \: parllalogram \: stand \: on \: common \: base (28cm)$

$= > area \: </strong><strong>of</strong><strong> \: triangle \: is \: = \: \: the \: area \: of \: parallalogram.......(given)$

• So let's find the area of the traingle

Sides = (28,30,26) cm

so Semiperimeter or s=

$\frac{28 + 26 + 30}{2}$

$\frac{84}{2}$

$42$

So area is =

$\sqrt{s(s - a)(s - b)(s - c)}$

$\sqrt{42(42 - 30)(42 - 28)(42 - 2)}$

$\sqrt{42 \times 12 \times 14 \times 16}$

$\sqrt{3 \times 2 \times 7 \times 3 \times 2 \times 2 \times 7 \times 2 \times 2 \times 2 \times 2 \times 2}$

$3 \times 7 \times 2 \times 2 \times 2 \times 2$

$16 \times 21$

346 cm²

A/Q, Area of traingle = Area of parallelogram

So area of parallelogram is = 346cm²

$now \: area \: of \: parallalogram \: = 346 \: cm^{2}$

$\frac{1}{2} \times common \: base \times height = 346$

$\frac{1}{2} \times 28 \times height = 346$

$14 \times height = 346$

• Height = 24.7cm