Question

Hey Guys Help Please♥️
Charges q1 = 100 u C and q2= 50 u C are located in xy-plane at positions r1 = 3.0 j and
r2 = 4.0 i respectively. Where the distance is measured in meters. Calculate the force
on q2
(a) 1.8 N
(b) 2.5 N
(C) ZN
(d) 8N
​

Answer 1

Answer:

hєчα mαtє

σptíσn (в) íѕ cσrrєct

plz mαrk αѕ вrαnlíѕt

Answer 2

Answer:

option (a) is correct => 1.8 N

Explanation:

q1 = 100uC = 1×10^(-4)C, q2 = 50 uC = 5×10^(-5)C

coordinate of charges q1 : (0,3) and q2 : (4,0)

distance between these (r)

= √ 3²+4⁴ = 5 meter

=> F =( 1/4π€o) q1q2/r²

= 9×10⁹×10^(-4)×5×10^(-5) /25

= 9/5

= 1.8 N

=> option (a) is correct.

Hope this helps you