HEY GUYS❣️❣️
⭐HERE IS A QUESTION FOR YOU ⏩
✨FROM CLASS 10TH (MATHS)
✌️CHAPTER 13 (SURFACE AREA AND VOLUME)
♥️BEST ANSWER WILL BE BRAINLEST..✌️✌️(^_^)♥️
ẞhrùtî Jhà Ør Ñîßhú
Answers
radius of bigger cylinder = 12 cm, height of bigger cylinder = 220 cm
Radius of smaller cylinder = 8 cm, height of smaller cylinder = 60 cm
Volume of bigger cylinder
=πr2h=πr2h
=π×122×220=π×122×220
=31680π cm3=31680π cm3
Volume of smaller cylinder
=πr2h=πr2h
=π×82×60=π×82×60
=3840π cm3=3840π cm3
Total volume
=31680π+3840π=35520π cm3=31680π+3840π=35520π cm3
Mass = Density x volume
=8×35520π=8×35520π
=892262.4 gm=892.3 kg
Answer:
892.26 kg
Step-by-step explanation:
First Cylindrical Part:
Height of cylinder = 220 cm.
Diameter = 24 cm.
Then, radius = 12 cm.
Volume of cylinder(V₁) = πr²h
= (3.14) * (12)² * 220
= 99475.2 cm³
Second Cylindrical Part:
Height of cylinder = 60 cm.
Radius = 8 cm
Volume of cylinder(V₂) = πr²h
= (3.14) * (8)² * 60
= 12057.6 cm³
Total Volume of pole:
Volume of 1st cylindrical part + Volume of 2nd cylindrical part
= 99475.2 + 12057.6
= 111532.8 cm³
Given, mass of 1 cm³ iron = 8g.
Mass of 111532.8 cm³ = 111532.8 * 8
= 892262.4 g
= 892.2624 kg.
Therefore, Mass of the pole = 892.2624 kg.
Hope it helps!