Question

Hey Guys!
Here's one which is from Ch-4, class-8,physics, USA.
Refer to the attachment.

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Also thanks to mathdude sir for helping me with my previous question.​

Answer 1

Answer:

h=Rcos45

=

2

R

Change in potential energy =mgh

2

1

mv

2

+

2

1

mu

2

=mgh

v

2

+u

2

=2gh⟶(1)

By momentom conservation,

mu=m(vcos45°−u)=m

2

v

v=2

2

u⟶(2)

Equation (1) becomes,

2u

2

+u

2

=2gh

u

2

=

3

2

gh

2

1

mu

2

+

2

1

m(vcos45°−u)

2

+

2

1

m(vsin45)

2

=mg

2

R

u

2

+(

2

v

−u)

2

+(

2

v

)

2

=

2

gR⟶(usingv=2

2

u)

u

2

+u

2

+4u

2

=

2

gR

6u

2

=

2

gR

u=

3

2

gR

Answer 2

Answer:

BTW u already found your answer

Explanation:

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