Question

Hey guys I have a very interesting question
Find the charge of 27g of Al^3+ ions in coulombs.

Answer 1

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Answer is in attachment....
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Answer 2

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• One Al3+ ion has charge of 3 protons, and a proton has the Same magnitude of charge as that on an electron.

No. of Al3+ ions = wt. in g/at. wt.

27/27 = 1

No. of Al3+ ions in 27 g = no. of moles × Av. Const.

$\implies$ 1 × 6.022 × 10^23

Change of 27g of Al3+ ions = 3 × charge of a proton × no. of Al3+ ions

$\implies$ 3 × 6.022 × 10^-19 × 6.022 × 10^23

$\implies$ 2.894 × 10^5 coulomls.

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