Question

hey guys! I hope you can help me with this question.: find a point on the y axis which is equidistant from the point A(5,6) and (3,-4). Thanking in advance​

Answer 1

Step-by-step explanation:

let the point be (0,y)

By using distance formula find distance btwn (0,y) and A(5,6)

we get √71 - 12y + y^2

Again find distance btwn (0,y) and (3,-4)

we get √25+8y + y^2

71 - 12y + y^2 = 25 + 8y +y^2

by solving we get

y = 23/10= 2.3

the point will be (0,2.3)

Answer 2

Answer:

answer is 0, 2.3

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