Question

hey guys! I hope you can help me with this question.: find a point on the y axis which is equidistant from the point A(5,6) and (3,-4). Thanking in advance​

Answer 1

Answer:

Let the point on y-axis be (0,y).

By, Distance formula we have,

D=(x2−x1)2+(y2−y1)2

Therefore,

(4)2+(y−3)2=(−6)2+(y−5)2

16+y2+9−6y=36+y2+25−10y

25−6y=61−10y

4y=36

y=9

Hence, the required point is (0,9)