Hey guys! I need a quick answer to this question please help me...
The unit vector along xi+yj is:
a. 1 b.square root under (x square + y square)
c.xi +yj / square root under (x square + y square) d. x/square root under (x square + y square) vector i + y/square root under (x square - y square) vector j
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Hola User______________
Here is Your Answer....!!!!!
______________________
☆Actually welcome to the concept of Vectors and its application and unit vector...
☆Basically we know that a unit vector along its direction is given as .....
☆Unit vector = the vector divided by its own magnitude .....
☆thus U cap = U vector / Modulus of U .....
☆since here the vector is xi + yj....then the unit vector will be ....
☆xi + yj / square root of x^2 + y^2 ......
☆ since we know that i^2 and j^2 will be 1.....
☆thus the option will be C.) .
________________________
Hope this helps u......☺
Here is Your Answer....!!!!!
______________________
☆Actually welcome to the concept of Vectors and its application and unit vector...
☆Basically we know that a unit vector along its direction is given as .....
☆Unit vector = the vector divided by its own magnitude .....
☆thus U cap = U vector / Modulus of U .....
☆since here the vector is xi + yj....then the unit vector will be ....
☆xi + yj / square root of x^2 + y^2 ......
☆ since we know that i^2 and j^2 will be 1.....
☆thus the option will be C.) .
________________________
Hope this helps u......☺
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