Question

hey guys i need some help from u guys
verify that -3 and 5 are the zero of the polynomial q(x)= (x+3)(x-5)​

Answer 1

Answer:

$= 1 > .4y}^{2}$

Answer 2

Answer:

q(x)=(x+3)(x-5)

1st step

Now put - 3 in place of x

q(-3)=(-3+3)(-3-5)=0×-8=0

Hence - 3 is a zero of the polynomial

Now put 5 in place of x

q(5)=(5+3)(5-5)=8×0=0

Hence 5 is a zero of the polynomial