hey guys,
If (1,p/3) is the mid points of the line segment joing the points (2,0) and (0,2/9), the show that the line 5x+3y+2=0 passes through the points (-1,3p)
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hey mate,
let (x2,y1) = A (2, 0)
(x2,y2) = B (0,2/9);
mid point of joining of A and B
= (x1 + x2/2, y1 + y2/2)
(1 , p/3). = (0+2/2,
0+2/9/2)
= (1, 119)
p/3 = 119
[therefore, if (a,b)=(c,d) then a=c and b=d]
p= 1/3 ------(1)
according to the problem given
put (-1,3p) in the equation 5x+3y+2=0
5(-1)+3×(3p)+2=0
-5+3×3(1/3)+2=0 [from(1)]
-5+3+2=0
0=0 (true)
therefore,
5x+3y+2=0 line passes through the point
(-3 , 3p)
ι нope тнιѕ нelpѕ yoυ!
@vaιвнav246
let (x2,y1) = A (2, 0)
(x2,y2) = B (0,2/9);
mid point of joining of A and B
= (x1 + x2/2, y1 + y2/2)
(1 , p/3). = (0+2/2,
0+2/9/2)
= (1, 119)
p/3 = 119
[therefore, if (a,b)=(c,d) then a=c and b=d]
p= 1/3 ------(1)
according to the problem given
put (-1,3p) in the equation 5x+3y+2=0
5(-1)+3×(3p)+2=0
-5+3×3(1/3)+2=0 [from(1)]
-5+3+2=0
0=0 (true)
therefore,
5x+3y+2=0 line passes through the point
(-3 , 3p)
ι нope тнιѕ нelpѕ yoυ!
@vaιвнav246
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