hey guys .....
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in a tug of war a 100 kg mass is hanged from the midpoint of the rope. The force that each side should exert to make the rope horizontal again is ???
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For ce exerted by Mass = mg
F = 980N
Then 490N force should be exerted on both sides...
F = 980N
Then 490N force should be exerted on both sides...
Atithisharma:
answer is infinity: (
Yeah answer can be infinity because on both sides of rope force is exerted in x-direction and force ecerted by mass is in y direction... so we need infinite x-direction direction force to balance it....
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Answer:
Infinite, of course. No horizontal force, however large, can counteract the effect of gravity, which is vertical. If the ropes make an angle theta w.r.t. the horizontal, the vertical component of the force is F Sin(theta) which must balance mg. Clearly, as theta becomes smaller and smaller, making the rope more and more horizontal, the required force becomes larger and larger!
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