Question

Hey guys, it's the question of class 12, physics,
Find the equivalent capacitance between A and B in the following network.

Answer 1

1/Req. = 136/120

So equivalent capacitance = 120/136 = Req. = 15/17

I have assumed Capacitors as "R" .

Plases don't get confused and estimate it as Resistance.

Answer 2

Answer:

Equivalent capacitance is 60/61 F.

Explanation:

Let us connect a potential difference across A and B.

Observe the provided picture and labelling of the capacitors,

When current crosses first 3 F capacitor at A, current splits in two.

So capacitors 2, 3, 4 are in series.

Let  equivalent capacitance of 2,3,4 be C₁ then.

1/C₁ =1/3 + 1/2 + 1/3

1/C₁ = 2/3 + 1/2

1/C₁ = 7/6

C₁ = 6/7 F

This is parallel to capacitor number 5.

Let C₂ be equivalent resistance of capacitor number 5 and C₁

C₂ = 6/7 + 2

C₂ = 20/7 F.

Now capacitor 1, 6 and C₂ are in series. Let their equivalent capacitance be C.

Therefore 1/C = 1/3 + 1/3 + 7/20

1/C = 2/3 + 7/20

1/C = 40+21/60

C = 60/61 F.