Question

hey guys, let's check your IQ level please solve this riddle

_+_+_=30
the numbers you can use in the dash are as follows
1,3,5,7,9,11,13,15 {only odd numbers}
Instructions-
• don't repeat any number
• don't spam
• for answer follow me ​

Answer 1

Answer:

+ + = 30

Conditions:

The used numbers should be odd numbers

Each odd numbers shouldn't repeat

Limit of odd numbers = 1 , 3 , 5, 9 , 11 , 13 , 15

Now,

Answer:

Let

Dash no. 1 be x

Dash no. 2 be y

Dash no. 3 be z

Now,

Adding all the limit of all given odd numbers

→ 1 + 3 + 5 + 9 + 11 + 13 + 15 = 64

→ (1 + 3 + 5 + 9 + 11 + 13 + 15) - 64 = 0

It can be written as

→ 64 - ( 1 + 3 + 5 + 9 + 11 + 13 + 15 ) = 0

→ 64 - 1 - 3 - 5 - 9 - 11 - 13 - 15 = 0

Here,

We should use only 3 numbers in the given limit

So, taking

x = - 11

y = - 13

z = 64. [ °.° Already we have ]

Substituting we have

→ 64 - 11 - 13

→ 64 - 24

→ 30

Hence , proved !

Answer 2

Answer:

Answer:

$\large\boxed{\fcolorbox{black} {black}{\color{yellow}{ANSWER}}}$

_+_+_= 30

Conditions:

The used numbers should be odd numbers Each odd numbers shouldn't repeat Limit of odd numbers = 1,3,5, 9, 11, 13, 15

Now,

Answer:

Let

• Dash no. 1 be x
• Dash no. 2 be y
• Dash no. 3 be z

Now,

Adding all the limit of all given odd numbers

$\implies 1+ 3 + 5 + 9 + 11 + 13 + 15 = 64$

$\implies (1 +3 +5 +9 + 11 + 13 + 15) - 64 = 0</p><p>$

We can write it as —>

$\implies 64 - (1+3+5 +9 + 11 + 13 + 15 ) = 0</p><p>$

$\implies 64 - 1-3 - 5 - 9 - 11- 13 - 15= 0$

Here,

We should use only 3 numbers in the given limit

So, taking

• x = - 11
• y = - 13
• z = 64.

[ Already we have ]

Substituting we have

$\rightarrow 64-11 - 13$

$\rightarrow 64 - 24$

$\rightarrow 30$

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