Hey guys......need a hand..! QUESTION:- Joseph jogs from the one end A to the other end B of a straight 300m road in 2 minutes 30 seconds and then turns around and jogs 100 m back to point C in another one minute. What is Joseph's average speed and velocity (a) from A to B (b) from A to C? No spam please❌❌
Answers
Answered by
4
Answer:
From pont A to B
Distance covered=300m
Displacement=300m
Time taken=2 min 30 sec=(2×60)+30=150 sec
Average speed=
Timetaken
Distance covered
=
150
300
=2 m/sec
Average velocity=
Timetaken
Displacement
=
150
300
=2 m/sec
From point A to C
Distance covered=300+100=400m
Displacement=300−100=200m
Time taken=3 min 30 sec=(3×60)+30=210 sec
Average speed=
Timetaken
Distance covered
=
210
400
=1.90 m/sec
Average velocity=
Timetaken
Displacement
=
210
200
=0.95 m/sec
Answered by
12
Explanation:
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