Question

Hey guys !

NEED PROPER AND CORRECT ANSWER WITH FULL STEPS AND EXPLANATIONS !

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Q. A Bomb is dropped from an aircraft when it is directly above a target from the height of 1500 mts. The aircraft is moving with velocity 600 km/hr by how much distance it misses the target ?

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CLASS 11TH PHYSICS CH :- MOTION IN PLANE !

NO SPAMS PLEASE !

CONTENT QUALITY ANSWER REQUIRED !

Answer 1

Hey MATE!!!

First we calculate the time for the bomb to reach the ground by applying Newton's equation in vertical direction;

T = √(2h/g) => √(2*1500/10)

=> √2*150 = 10√3 sec.

Now the distance between the target and the place where the bomb falls can be calculated by :

Distance = speed * time

$(600 \times \frac{5}{18} ) \times 10 \sqrt{3} \\ \\ = > \frac{500 }{3} \times 10\sqrt{3} \\ \\ = > \frac{5000}{ \sqrt{3} } m = \frac{5}{ \sqrt{3} } km$

The answer is little complicated because I have converted units to meter and seconds.

Hope it helps

HAKUNA MATATA :))